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Deflection and crack control

How a beam is checked in service to EN 1992-1-1, on the Eurocode 2 route of the STATIX RC beam calculator: span over depth with K and the steel ratio (7.4.2), long-term deflection by calculation (7.4.3), the bar size and spacing rules (7.3.3) and the crack width (7.3.4).

1. Learning outcomes

After this lesson you can:

  • check a beam’s deflection by span over depth with eq 7.16 and the 7.17 adjustment;
  • explain how creep, shrinkage and cracking make a beam sag over time;
  • work out the minimum steel for crack control;
  • control cracks by bar size or spacing, and calculate a crack width;
  • read the calculator’s serviceability results, and know when the rule and the calculation disagree.

2. Before you start

The values this lesson uses are those of the calculator’s Eurocode 2 route: Table 7.4N K factors and eq 7.16 with the 7.17 factor As,prov/As,req (up to 1.5); the quasi-permanent load with ψ2 (0.3 by default) for the crack width and the calculated deflection; default creep and shrinkage from 3.1.4 and Annex B; wmax 0.3 mm; kt 0.4 and the recommended k1 to k4 in eq 7.11.

3. Deflection

atotal, quasi-permanent: a ≤ L/250 (appearance)after the partitions are built: a ≤ L/500
Deflection limits. EN 1992-1-1 7.4.1 suggests span/250 for the total sag under the quasi-permanent load, for appearance, and span/500 for the part that happens after partitions and finishes are fixed. The calculator’s default limit is L/250 (total).
span / d ≤ K × basic ratio (7.4.2, eq 7.16)K = 1.0simply supportedK = 1.3end spanK = 1.5interior spanK = 0.4cantileverthe basic ratio depends on the steel ratio ρ and fck
Span over depth. Most beams and slabs are checked for deflection without a calculation: the span over the effective depth must not exceed a limit. K allows for the support conditions (Table 7.4N gives the values).
ρ0 = √fck × 10−3basic l/dρ = As,req/(b d)
The basic ratio. Lightly reinforced members may be much more slender than heavily reinforced ones. Eq 7.16a applies when the tension steel ratio ρ is below ρ0, eq 7.16b above it (with compression steel ρ′ added). The curve is for C30/37 with no compression steel.
× 310/σs≈ As,prov/As,req (7.17)≤ 1.5the most it may addflanges beff/bw > 3: × 0.8; spans over 7 m: × 7/l
Adjusting the ratio. Extra steel lowers the steel stress, so the beam cracks less and sags less: the ratio may be raised by As,prov/As,req, up to 1.5. Wide flanges and long spans lower it (7.4.2(2)).
instantwith creep and shrinkagetime
Long-term deflection. Under a sustained load the concrete creeps, and as it dries it shrinks; both add sag for years. The calculator works with an effective modulus Ec,eff = Ecm/(1 + φ) and a shrinkage curvature, with default φ and εcs from 3.1.4 and Annex B that you can change.
cracked: Icrζ = 1 − 0.5 (Mcr/M)²1/r = ζ/rcracked + (1 − ζ)/runcrackedeq 7.18 and 7.19
Between cracked and uncracked. A real beam is cracked near mid-span and uncracked near the supports, and the concrete between the cracks still helps. EN 1992-1-1 7.4.3 interpolates the curvature between the two states with ζ. The calculator takes Mcr of the first loading (the uncracked section with Ecm) and counts the beam as cracked when the quasi-permanent or the characteristic moment passes it (7.4.3(3)).

4. Cracks

wmax 0.3 mm in the calculator (quasi-permanent load)cracks at the tension face are normal; their width is controlled
Crack control. Reinforced concrete always cracks in tension; the aim is to keep the cracks fine, for durability and appearance. Table 7.1N recommends limits by exposure class; the calculator checks against 0.3 mm for every class, which for X0 and XC1 is stricter than the recommended 0.4 mm.
As,min = kc k fct,eff Act / σs (7.3.2, eq 7.1)kc = 0.4bendingk = 1.0 to 0.65h 300 to 800 mmActthe tension zone
Minimum steel for cracking. When the concrete cracks, the tension it carried jumps into the steel; there must be enough steel not to yield at once, or a few wide cracks form. This is a separate minimum from the strength minimum of lesson 1.
bar sizemax φ for σs (Table 7.2N)orbar spacingmax s for σs (Table 7.3N)σs: the steel stress under the service load
Control without calculation. If the bars are small enough or close enough together for the steel stress they work at, the cracks will be within the limit (7.3.3). Either table is enough. The calculator’s checks use the spacing table, with the steel stress from the characteristic load (on the safe side).
wk = sr,max (εsm − εcm) (7.3.4, eq 7.8)sr,max = 3.4 c + 0.8 × 0.5 × 0.425 φ/ρp,eff (eq 7.11)εsm − εcm = [σs − kt fct,eff/ρp,eff (1 + αeρp,eff)]/Es≥ 0.6 σs/Es; kt = 0.4 (long term)
Calculating the crack width. The widest crack is the largest crack spacing times the difference between the steel strain and the concrete strain. The calculator does this for each span under the quasi-permanent load.
hc,efhc,ef = min(2.5(h − d), (h − x)/3, h/2)
The effective tension area. Only the concrete close to the bars is held together by them: an area hc,ef deep around the tension steel. ρp,eff = As/Ac,eff measures how well that area is reinforced.

5. Example A: the lesson 1 beam in service

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6. Example B: a long, slender beam

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7. Do it in STATIX

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8. Common mistakes

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9. Exercises

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10. Self-check quiz

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11. Lesson 4 on one page

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Next: Lesson 5, columnsSlenderness, imperfections, nominal curvature and biaxial bending.
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