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Combined axial force and bending

Real columns carry moments and real beams can carry axial force. This lesson shows how SANS 10162-1 combines the two, why the moment is amplified, and how to check a beam-column by hand and in the STATIX steel member calculator.

1. Learning outcomes

After this lesson you can:

  • explain the interaction of axial force and bending and the second-order amplification U1;
  • choose ω1 from the end moments and find Ce about each axis;
  • carry out the 13.8.2 checks (a), (b), (c) and the extra biaxial check, and say which governs;
  • tell braced from unbraced members and use 13.9 for tension with bending;
  • check a beam-column in the STATIX steel member calculator.

2. Before you start

3. What a beam-column is

N from the floors aboveM from the beamsbows: N adds moment
A beam-column carries axial force and bending at the same time: a column with beams framing in off-centre, a portal rafter, a truss chord with loads between nodes. Each action alone is easy; together they use up the same steel.
Cf / Cr = 1Mf / Mr = 1safebending usedaxial used
The interaction idea. Add the share of the axial resistance used to the share of the bending resistance used; the total must not pass 1. SANS 10162-1 (13.8) refines this straight line with factors for the moment shape, the amplification and the section class.

4. Amplification

Cδthe bow adds C × δamplified moment = U1 × MU1 = ω1 / (1 − Cf / Ce)Ce = π²EI / (KL)² per axisthe closer Cf gets to Ce, the bigger U1
Second-order amplification (SANS 10162-1, 13.8.4). The axial load acting on the bowed member adds moment, which bows it more. U1 estimates the result: it grows as Cf approaches the Euler load Ce of the axis in question.
xyCex = π²EIx / KLx²Cey = π²EIy / KLy²Cey is much smaller:U1y amplifies more
The Euler load Ce of each axis, with that axis's effective length, sets its amplification. STATIX uses the same per-axis lengths as for Cr.
single curvatureκ = −1ω1 = 1.0one end zeroκ = 0ω1 = 0.6double curvatureκ = +1ω1 = 0.4 (floor)ω1 = 0.6 − 0.4κ ≥ 0.4 (no load between the ends)
ω1 (13.8.4) turns an uneven moment into an equivalent uniform one. Equal end moments bending the member one way are the worst case (1.0); a member bent into an S needs much less. The STATIX page takes ω1x and ω1y typed, 0.4 to 1.0, default 1.0 (safe).
Ce = π² E I / (KL)² for each axis U1 = ω1 / (1 − Cf/Ce) (13.8.4) ω1 = 0.6 − 0.4 κ ≥ 0.4 (κ = Msmall/Mlarge, positive for double curvature) U1x is not taken less than 1.0

5. The checks (SANS 10162-1, 13.8.2 and 13.8.3)

(a) cross-sectionCr at λ = 0; U1 ≥ 1; 0.6 on Mybraced frames only(b) overall memberCr from 13.3; Mrx = φZFyβ on the weak-axis term(c) lateral-torsionalMrx from 13.6 (LTB)β on the weak-axis termin additionMfx/Mrx + Mfy/Mry ≤ 1biaxial bendingCf/Cr + 0.85 U1x Mfx/Mrx + β U1y Mfy/Mry ≤ 1
SANS 10162-1, 13.8.2 for class 1 and 2 I-shaped sections: three versions of the same sum, each with a different Cr and Mrx, plus a check of the moments alone. The largest result governs. For all other sections (13.8.3) the 0.85 and β become 1.0.
class 1 or 2 I-shape13.8.20.85 on Mx, β on Myall other sections13.8.3factors 1.0the class comes from the section (lesson 3)
Which clause. The extra factors of 13.8.2 are earned by the plastic reserve of stocky I-sections. Class 3 sections, channels, tubes and angles use 13.8.3. STATIX picks the clause from the class.
MxMyweak-axis moments are costly:Mry is small, and U1y is largebecause Cey is lowβ = 0.6 + 0.4 λy ≤ 0.85(13.8.2 b and c)
The weak axis. An H-section is much weaker and more flexible about its minor axis, so even a small My (a beam bearing on one flange, a wind load on the side) can use a large share of the resistance. β scales that term with the weak-axis slenderness.

6. Braced and unbraced; tension with bending

BracedUnbraced (sway)U1 from 13.8.4U1 = 1.0; sway in the moments
Braced or unbraced. In a braced frame the member's own bow is amplified by U1. In an unbraced frame U1 = 1.0 and the sway effects must already be in the moments, from a second-order analysis or amplified first-order moments; the STATIX page has no separate sway factor. If you do not choose, the page uses the larger of the two results.
tension + bending (13.9)Tf/Tr + Mfx/Mrx + Mfy/Mry ≤ 1STATIX: Tr = φ Ag Fy here;net fracture and block shearare separate tension checkswith N = 0 this row is plain bending
A member in tension with bending, such as a truss bottom chord with a load between nodes, uses the simple sum of 13.9. Tension straightens the member, so there is no amplification. The STATIX page reports pure bending (N = 0) under this same row.

7. In STATIX

N > 0Mx, MyKL, LTBlength, ω2ω1x, ω1y0.4 to 1.0framebraced / sway
The beam-column route in the STATIX steel member calculator: N (positive for compression), Mx, My; the effective length, LTB length and ω2; under More inputs ω1x, ω1y and the frame type. The calc sheet lists every check (a), (b), (c) and which one governs.

8. Example A: a braced UC column with end moments

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9. Example B: add a small weak-axis moment

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10. Do it in STATIX

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11. Common mistakes

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12. Exercises

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13. Self-check quiz

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14. Lesson 4 on one page

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Next: Lesson 5, bolted connectionsFrom members to joints: bolts in shear and bearing, bolt groups and fin plates.
Go to lesson 5

A worked example for learning, not a design. Check every value against the current code and your own project, and have the design checked and signed by a registered professional engineer.

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